> On 7. May 2017, at 21:27, Thom L <[email protected]> wrote: > > Hi Bastian, > > Le 7 mai 2017 22:10, "Bastian Bloessl" <[email protected]> a écrit : > > The red line is the complex component (which is around 0), while the blue > line shows the real part (which jumps between 1 and -1). > > Yes but it jumps at sample rate 20M and not 6M?
IEEE 802.11a/g always uses 20MHz channels independent from the modulation and coding scheme. So it will always be a signal with a 20MHz bandwidth. If you encode data with BPSK and a coding rate of 1/2, the 20MHz signal will carry 6Mbit/s (bits per second, not bandwidth in frequency domain). > What I would is to see the bit rate If you want to visualize the data throughput, I would recommend to parse the Wireshark output and calculate a moving average. But you won’t see the 6 MBit/s. It’s only the PHY throughput, which you could only reach if you sent a single frame with infinite size. Best, Bastian _______________________________________________ Discuss-gnuradio mailing list [email protected] https://lists.gnu.org/mailman/listinfo/discuss-gnuradio
