Thanks Cinaed! I will test how it works.
George On Sat, Jan 23, 2021 at 2:58 PM Cinaed Simson <[email protected]> wrote: > Hi George - I'm presuming the enclosed example.py script is what you're > trying calculate - and that the input data is complex. > > I invented my own data. > > If true, it should be easy to adapt it to your problem by combining the 2 > loops for any value of n. > > -- Cinaed > > > On 1/22/21 10:49 AM, George Edwards wrote: > > Hello, > I am working with the OOT Interpolator template and I set the > interpolation factor to 2. In the QA file I input 5-complex samples and > based on my simple code below in the work() method, I expect the QA test to > return 1+j1, 10-times (5x2). The QA returns ((1+1j), (1+1j), 0j, 0j, 0j, > 0j, 0j, 0j, (1+1j) , (1+1j)). I have tried a lot of different coding > permutations and this is the closest I come to a solution, but it is > wrong!!! Any help is greatly appreciated! > > def work(self, input_items, output_items): > > in0 = input_items[0] > > out = output_items[0] > > for ii in range(0,len(in0)): > > for k in range(0,2): > > out[k] = 1.0+1.0*1j > > > > return len(output_items[0]) > > Thanks, > George > > >
