Is this only true if the effects are specified on one line? In other words,
would the following also queue?
$("#foo").slideDown('slow');
$("#foo").slideUp('slow');
The reason I ask is that there are some cases I've seen where rapid effects
on elements go screwy. A good example of this is to rapidly select different
tabs on the excellent $.tabs plugin <http://www.stilbuero.de/jquery/tabs/>.
If you try this, make sure you use the tabs that trasition with effects
(e.g. Slide Effect tabs 7-9)
John Resig wrote:
>
>> I believe that jQuery has a sort of built in queue in that effects are
>> chainable. So you'd simply write all of the effects in one long chain and
>> each of them would happen in the order you specify in your chain.
>
> Exactly, so doing:
>
> $("#foo").slideDown('slow').slideUp('slow');
>
> will be queued completely.
>
> --John
>
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