Have you already written this?

On Thu, 2006-10-12 at 16:16 -0700, Ⓙⓐⓚⓔ wrote:
> this is a helluva plugin... totally without html additions, and the
> magic just happens!
> /*
>  *
>  * TableSorter - Client-side table sorting with ease!
>  *
>  * Copyright (c) 2006 Christian Bach (http://motherrussia.polyester.se)
>  * Licensed under the MIT License:
>  * http://www.opensource.org/licenses/mit-license.php
>  *
>  * $Date: 2006-08-21 14:43:23 +0000 (må, 21 aug 2006) $
>  * $Author: Christian $
>  *
>  */
> 
> 
> On 10/12/06, Adrian Sweeney <[EMAIL PROTECTED]> wrote:
> > Hi guys today I finally got around to using jQuery today and man do i
> > love it.  wished that I had known about it before I started my last
> > project. would have saved me a couple of months work.
> >
> >
> > Ok well back to today
> >
> > I needed to take a structure (table made of div's) and sort by
> > alphabetic order once I got my head around the way that jQuery worked my
> > boss who had used jQuery more showed me the exact code I needed for
> > doing the sort.  what you have two css selector definitions, one  for
> > the rows of your data and the other is the css selector information for
> > the element that holds the information that you want to sort on
> >
> > basically what you would end up with is
> >
> > $.sort("table.report tbody tr", "td.name a");
> >
> > would sort the following table into alphabetic order
> >
> > <table class='report'>
> >   <thead>...</thead>
> >   <tbody>
> >     <tr><td class='name'><a href='zebra.html'>zebra</a></td><td>Looks
> > like a horse with stripes</td></tr>
> >     <tr><td class='name'><a href='tiger.html'>tiger</a></td><td>Looks
> > like a horse with stripes but with sharp teeth.</td></tr>
> >   </tbody>
> > </table>
> >
> > I think that this would be a great addition to the jQuery base class or
> > should it just be a plugin.
> >
> > $(document).ready(function(){
> >   var rows = [];
> >   $("table.report tbody tr").each(function(){
> >     rows[rows.length] = [$(this).find("td.name a").html(),this];
> >   });
> >   rows.sort(function(a,b){
> >     if (a[0] < b[0]) {
> >       return -1
> >     } else if (a[0] > b[0]) {
> >       return 1
> >     } else {
> >       return 0;
> >     }});
> >   $.each(rows, function() {
> >     this[1].parentNode.appendChild(this[1]);
> >   });
> > });
> >
> > I'll look into adding this to the jQuery-latest.js code later
> >
> > Adrian Sweeney
> >
> >
> >
> > ___________________________________________________________
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> >
> >
> >
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> >
> >
> >
> 
> 

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