This works except that it has the unfortunate effect of
moving things after they've faded. Which makes complete sense but is almost
useless since the elements visual render one way and then the
other.
Is this something that can be "fixed" in jQuery or does my
design just need to take this into account?
Thanks!
Chris.
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Yehuda Katz
Sent: Monday, October 30, 2006 4:36 PM
To: jQuery Discussion.
Subject: Re: [jQuery] fadeIn() causes change in page layout
$(expr).fadeIn(500, function() { $(this).css("display", "inline") })
-- Yehuda
On 10/30/06, Chris W.
Parker <[EMAIL PROTECTED]> wrote:
Hello,I'm just beginning to play with jQuery and as well I'm a novice with js.I'm just doing some VERY simple tests right now and I ran into some unexpected behavior.The following HTML will render on the same line in your browser:<a class="one" href="">...</a><a class="two" href="">...</a>But when I apply fadeIn() to either of those elements they (appear to) turn into block elements thus rendering them on separate lines.Is this to be expected?Thanks,Chris.
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Yehuda Katz
Web Developer | Wycats Designs
(ph) 718.877.1325
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