escape() and unescape() have always worked for me :-)
i.e.
escape('The quick brown fox') -> The%20quick%20brown%20fox
unescape('The%20quick%20brown%20fox') -> The quick brown fox
Luke
Truppe Steven wrote:
> Mark Gibson schrieb:
>
>> Javascript has the functions:
>>
>> decodeURI(s) and decodeURIComponent(s)
>>
> I get a string like this:
>
> Stumpf+einer+Palme%2C+ausgeh%F6hlt%2C+geschliffen+und+mit+Perlmutteinlegearbeiten+verziert
>
> If this string is inside the variable "test" and i do:
> var newtest = decodeURIComponent(test);
>
> I get the error "malformed URI sequence".
>
> I've looked documentation on
> http://developer.mozilla.org/en/docs/Core_JavaScript_1.5_Reference
> but there i don't see much about that function...
>
> Thanks for the fast reply! What am i doing wrong ?
>
>
> best regards,
> Truppe Steven
>
>
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