On 12/17/06, Karl Swedberg <[EMAIL PROTECTED]> wrote:
thanks, everyone, for the suggestions and questions.
regarding Yehuda's suggestion:
$(".class > .otherClass tr#id td#id") into $("#id").filter(".class >
.otherClass tr#id td")
a small clarification: If #id is an ancestor of .class, we'd probably want
to use .find() instead of .filter() . . .
$('#id').find('.class > .otherClass tr#id td')
$('#id').find('.class > .otherClass tr#id td') would be equally optimized as
$("#id .class > .otherClass #tr#id td"), so that wasn't the situation I was
talking about ;)
-- Yehuda
Also, a hat tip to Aaron Heimlich, who blogged about this issue, unbeknownst
to me at the time, before I did.
http://aheimlich.freepgs.com/javascript/jquery-selector-speed/
--Karl
_________________
Karl Swedberg
www.englishrules.com
www.learningjquery.com
On Dec 17, 2006, at 8:53 AM, Yehuda Katz wrote:
It was a typo. My apologies.
A more robust solution might be to use filter:
$(".class > .otherClass tr#id td#id") into $("#id").filter(".class >
.otherClass tr#id td")
On 12/17/06, Klaus Hartl <[EMAIL PROTECTED]> wrote:
>
> Felix Geisendörfer schrieb:
> > Quick question:
> >> $(".class > .otherClass tr#id td#id") into $("#id").id(".class >
> >> .otherClass tr#id td")
> > Does this work? Or should the function be 'is' not 'id'?
> >
> > $(".class > .otherClass tr#id td#id") into $("#id").is(".class >
> > .otherClass tr#id td")
> >
> > I'm just wondering because I thought the 'id' function is used to set
> > the 'id' attribute of an element.
>
> I think that's a typo. Still it's not the same, because is() returns a
> boolean.
>
>
> -- Klaus
>
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--
Yehuda Katz
Web Developer | Wycats Designs
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_______________________________________________
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--
Yehuda Katz
Web Developer | Wycats Designs
(ph) 718.877.1325
_______________________________________________
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