I think you're going to have to loop through all of your elements to find
the max z-index and then either re-set them or just set the z-index
to max+1.
-js
On 1/11/07, Su <[EMAIL PROTECTED]> wrote:
No.
The whole problem is that there's a static number in that statement. So
eventually, all the panels end up with that same z-index, which makes them
revert to stacking in source order.
On 1/11/07, Joan Piedra <[EMAIL PROTECTED]> wrote:
>
> Can't you just use z-index in $(this)??
>
> onStop : function() {
> > $(this).css("z-index","10000");
> > }
>
>
>
> On 1/9/07, Su < [EMAIL PROTECTED]> wrote:
>
> > I've got something I'm building wherein several boxes will be
> > draggable. What I'd like to do is have a function that can be called when
> > dragging stops(Interface onStop), or just when a box is clicked that would
> > bring it to the top of the stack via the z-index.
> >
> > Of course, the writers of the CSS spec didn't think to just provide a
> > "top" value, so this isn't directly possible.
> > I tried something like just:
> >
> > onStop : function() {
> > $('.dragbox').css("z-index","1");
> > $(this).css("z-index","10000");
> > }
> >
> > but that ends up pretty obviously wrong, since it causes the other
> > elements to shuffle. They're all set to "1," and so end up in the natural
> > source-order stacking, rather than retaining their relative positions, just
> > under the currently active box.
> >
> > Is there a way to do this that isn't too involved? Speak to me like
> > someone who knows just enough JS to break other people's JS *grin*
> >
> > _______________________________________________
> > jQuery mailing list
> > [email protected]
> > http://jquery.com/discuss/
> >
> >
> >
>
>
> --
> Joan Piedra || Frontend webdeveloper
> http://joanpiedra.com/
> _______________________________________________
> jQuery mailing list
> [email protected]
> http://jquery.com/discuss/
>
>
>
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