you slap it up in any of your scripts... or a special one (just for debugging)
then you can insert .debug("any label") anywhere along the chain!
On 1/23/07, Daemach <[EMAIL PROTECTED]> wrote:
>
> Please don't forget that a noob started this thread ;) How do I use that
> code block?
>
>
>
> Ⓙⓐⓚⓔ wrote:
> >
> > Mike, I don't like breaking the chains... I just insert a debug in the
> > middle of the chain...
> >
> > I use this for my debug:
> > jQuery.fn.debug = function(message) {
> > return this.log('debug:' + (message || '')
> > +"[").each(function(){jQuery.log(this);}).log("]");
> > }
> > jQuery.fn.log = jQuery.log = function(message) {
> > if (!message) message = 'UNDEFINED'
> > if (typeof message == "object") message = jsO(message)
> > if(window.console && window.console.log) //safari
> > window.console.log(message)
> > else if(window.console && window.console.debug) //firebug
> > window.console.debug(message)
> > else
> > jQuery("body").prepend(message+ "<br/>")
> > return this
> > }
> >
> >
> > On 1/23/07, Michael Geary <[EMAIL PROTECTED]> wrote:
> >> > Is there a way to just return the jquery object (so I could
> >> > see it in firebug's watch section) then pass it to another
> >> > jquery function then join them all up when I know
> >> > everything works?
> >> >
> >> > $('#test :textarea').before('Current length: <span id="'+
> >> this.id +'_len">'+this.value.length+'</span> characters').keypress(
> >> function()
> >> > {
> >> > $('#'+this.id + '_len').css('color', ((this.value.length >
> >> parseInt(this.id.split()[1]))?'red':'green')).html(this.value.length)
> >> > });
> >>
> >> Yes, breaking up your chains is one of the first things do do when you're
> >> having trouble. For example:
> >>
> >> var $test = $('#test :textarea');
> >> $test.before('Current length: <span id="'+ this.id
> >> +'_len">'+this.value.length+'</span> characters');
> >> $test.keypress( function() {
> >> var $len = $('#'+this.id + '_len');
> >> $len.css('color', ((this.value.length >
> >> parseInt(this.id.split()[1]))?'red':'green'));
> >> $len.html(this.value.length);
> >> });
> >>
> >> Now you'll find it easier to debug.
> >>
> >> -Mike
> >>
> >>
> >> _______________________________________________
> >> jQuery mailing list
> >> [email protected]
> >> http://jquery.com/discuss/
> >>
> >
> >
> > --
> > Ⓙⓐⓚⓔ - יעקב ʝǡǩȩ ᎫᎪᏦᎬ
> > _______________________________________________
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> > [email protected]
> > http://jquery.com/discuss/
> >
> >
>
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>
>
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