I just tested using .hide() and .show() in Firebug with <a>
elements, and .show() only makes them elem.style.display="block" when
there is a speed designated. Plain .show() returns them to inline.
On Feb 14, 2007, at 5:37 PM, Michael Geary wrote:
The real problem here is that there is *no such thing* as "showing"
an HTML
element. All you can do is set it to block or inline. This suggests
that
show() is a mistake: you need separate showBlock() and showInline()
methods.
I wonder, would it be possible to pass in another argument instead?
Something like .show('slow', 'inline') ? Or would that require too
much code rewriting? Would have to consider the callback function too.
--Karl
_________________
Karl Swedberg
www.englishrules.com
www.learningjquery.com
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