I got burned by a debug plugin last night so I'm modifying a great object dumper to run as a jquery plugin. Dumping the entire jquery object is too much and not useful for this application - I only want the objects in the current selection set. If I do:
var tmp = $("p"); and there are 2 "p" elements on the page, the selection set is tmp[0] and tmp[1]. Is there another location in the object where these references reside? Or what is an elegant and fast way to strip just those items? Eventually I want to call this using $("p").dump() or $("p").debug() -- View this message in context: http://www.nabble.com/How-do-I-grab-just-the-selected-objects-out-of-the-jquery-object--tf3280273.html#a9123599 Sent from the JQuery mailing list archive at Nabble.com. _______________________________________________ jQuery mailing list discuss@jquery.com http://jquery.com/discuss/