Quick tut: Just typing something out, eg, /abcd/ would replace anything that contained the exact string "abcd", case sensative. If you do /[abcd]/, notice the brackets, it will select the letter "a", the letter "b", etc. For ranges you can do something like /[a-d]/, which would do the same as /[abcd]/. Remember that regex is case sensative, unless you add an "i" flag to the expression, like /[a-d]/i , which would find "a-d", and "A-D". Also, it will only replace the first instance, unless you add a "g" flag, so:
"once upon a time".replace(/o/,'O'); would make "Once upon a time", but: "once upon a time".replace(/o/g,"O"); would make "Once upOn a time" On 3/7/07, Ⓙⓐⓚⓔ <[EMAIL PROTECTED]> wrote:
1 command , 2 replaces var newString = oldString.replace(/X/,"-").replace(/Y/,"") On 3/7/07, Alexandre Plennevaux <[EMAIL PROTECTED]> wrote: > > > hello! > > I'm experimenting with regular expressions, and i would like to replace in a > string some special characters by a "-" minus sign, and others by just > removing it. > Do i need ot make two regex.replace(), or is it possible to have both in one > command? > > thank you very much for your time! > > Alexandre > > > > > > -- > Ce message Envoi est certifié sans virus connu. > Analyse effectuée par AVG. > Version: 7.5.447 / Base de données virus: 268.18.7/712 - Date: 6/03/2007 > 15:42 > > _______________________________________________ > jQuery mailing list > discuss@jquery.com > http://jquery.com/discuss/ > > -- Ⓙⓐⓚⓔ - יעקב ʝǡǩȩ ᎫᎪᏦᎬ _______________________________________________ jQuery mailing list discuss@jquery.com http://jquery.com/discuss/
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