Thank you, Mike, it works great this way! :-) Arne http://www.arnekolja.com
Mike Alsup wrote: > Try this: > > var securityCheck = "mysecuritycode"; > var formData = $("#myForm").formToArray(); > formData.push( { name: "security", value: securityCheck }); > ... > // replace "security" with whatever the correct "name" is. > > _______________________________________________ jQuery mailing list discuss@jquery.com http://jquery.com/discuss/