Hi Mario,
To get the second child, you can use the :nth-child(n) pseudo-class:
$('FIELD:nth-child(2)')
If you want all of the fields after the third, you can use :gt(n)
$('FIELD:gt(2)')
More fun ways to select elements can be found in the docs:
http://docs.jquery.com/DOM/Traversing
Also, I wrote a couple entries on learningjquery.com that might help:
http://www.learningjquery.com/2006/11/how-to-get-anything-you-want-
part-1
http://www.learningjquery.com/2006/12/how-to-get-anything-you-want-
part-2
Hope that helps.
--Karl
_________________
Karl Swedberg
www.englishrules.com
www.learningjquery.com
On Mar 23, 2007, at 9:14 AM, MARIO MOURA wrote:
Hi
I am newbie
How can I get a second children element?
In firebug I have
---DIV
------FIELD
------FIELD
------FIELD
------FIELD
------FIELD
My problem is all children have same name. How can I get second and
after the third...
Regards
--
macm
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