That did the ticket Jake. BEAUTIFUL solution! ++jake _____
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Jake McGraw Sent: Wednesday, March 28, 2007 3:24 PM To: jQuery Discussion Subject: Re: [jQuery] Close any other row before showing a new one Have to tried ':visible' selector? $('.hidden:visible').slideUp("fast"); - jake On 3/28/07, Alex Ezell < [EMAIL PROTECTED] <mailto:[EMAIL PROTECTED]> > wrote: I faced a similar issue with a project I was working on. I never found a solution. Of course, I also never bothered to post here (consider me easily distracted). I'll be interested to see what the solution is. /alex On 3/28/07, Andy Matthews < <mailto:[EMAIL PROTECTED]> [EMAIL PROTECTED]> wrote: I've got a series of rows of data, some of which can be expanded to show additional information. I'd like to hide any open row before showing a new one. I've tried hiding all of them (or sliding up) but the display goes wonky because most of them are NOT open. This is what a row looks like: <div id="specials-123456-details" class="hidden"></div> or <div id="newInv-997845-details" class="hidden"></div> I'm using slideToggle to open the row: $(child).html(data).slideToggle("fast"); and I've tried hiding them like so: $('.hidden').slideUp(); and $('.hidden').hide(); So I'm wondering, how can I get ONLY the ones that are open already? ____________________________________ Andy Matthews Senior Coldfusion Developer Office: 877.707.5467 x747 Direct: 615.627.9747 Fax: 615.467.6249 [EMAIL PROTECTED] www.dealerskins.com <http://www.dealerskins.com/> _______________________________________________ jQuery mailing list discuss@jquery.com http://jquery.com/discuss/ _______________________________________________ jQuery mailing list discuss@jquery.com http://jquery.com/discuss/
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