Having nothing better to do I've been pondering this. If a 16bit source is made up to 24bit by adding eight 0s on the end, then isn't it fair to say that there will be no loss of resolution if all you do is remove a few of them? Of course the signal will be closer to the noise floor, but what about resolution? e.g. (assuming 50% digital level control = an arithmetic division by 2) then simply removing one of the 0s will not reduce resolution.
Is the level control arithmetic? Take this a bit further. Remove all the 0s and the level will now be 1/256 with no loss in resolution. You're just back where you started. Since whole number multiplication does not have any effect on resolution then the original signal can be kept intact as long as the digital level control is kept to a multiple of 1/256. Perhaps the volume control should be made and marked as 1/256 -> 256/256, or at least do that in the background. In whole number % terms you only hit one of these "magic" numbers at 25, 50, 75, 100%. Any intermediate volume will introduce rounding errors. At the top end there will be eight spare bits to accomodate this, at the lower end this will be less. So does an arithmetic volume of 75% have better resolution than, say, 95%? Please note the Numpty Warning at the top. Please assist by spotting the logical/technical whoopsie. Looking forward to being set straight :) Keith -- KMorgan ------------------------------------------------------------------------- Sorry, can't spare enough hours today for that 5 min job on the computer. ------------------------------------------------------------------------ KMorgan's Profile: http://forums.slimdevices.com/member.php?userid=22838 View this thread: http://forums.slimdevices.com/showthread.php?t=75006 _______________________________________________ discuss mailing list [email protected] http://lists.slimdevices.com/mailman/listinfo/discuss
