Hi, and thanks for your help. I think I'm finally starting to get a
grip on how an application is supposed to be organized. The solution
looks like this:
>From web.xml:
<servlet>
<servlet-name>restservice</servlet-name>
<servlet-class>com.noelios.restlet.ext.spring.RestletFrameworkServlet</servlet-class>
<init-param>
<param-name>targetRestletBeanName</param-name>
<param-value>guard</param-value>
</init-param>
<load-on-startup>1</load-on-startup>
</servlet>
And then in my spring context file (restservice-servlet.xml):
<beans>
<bean id="guard" class="com.example.rest.MyGuardFilter">
<constructor-arg ref="someUserDao"/>
<property name="next" ref="root"/>
</bean>
<bean id="root" class="org.restlet.ext.spring.SpringRouter">
<property name="attachments">
<map>
...
</map>
</property>
</bean>
...other beans...
</beans>
I realise that I could name the change the bean IDs so that I don't
have to override the default of the RestletFrameworkServlet but I like
that the guard is pointed at explicitly.
Best Regards
Gabriel Falkenberg
On Tue, Oct 21, 2008 at 2:36 PM, Kevin Conaway <[EMAIL PROTECTED]> wrote:
> Both the Application class and SpringRouter classes are instances of Restlet
> so I don't believe you need an Application instance.
>
> Wherever you have injected your SpringRouter, simply inject your Guard class
> with the SpringRouter as the "next" property.
>
> Kevin
>
> On Mon, Oct 20, 2008 at 8:19 AM, Gabriel Falkenberg
> <[EMAIL PROTECTED]> wrote:
>>
>> Hi
>>
>> I wonder if there is a special way to add guards/filters to a Restlet
>> application when using the Spring extension. My application does not
>> seem to have a separate Application class, only a SpringRouter. Is an
>> Application class required for this?
>>
>> Best Regards
>> Gabriel Falkenberg
>
>
