Dear sir/maddam
I am using python Release 2.3.3, but I cant use it solving the following
python source code. Would you please help me in solving the following problem
using some other python release.
Exponentiation
Consider the following Python code: def expo(s,lm,N): return reduce(lambda
x,m: pow(x,m,N),lm,s) def hamming(a): return a>0 and (a%2)+hamming(a/2) or
0 def htot(k): n=pow(2,k) N=pow(2,n)-3 lm=[pow(i,i,N) for i in
range(1,n+1)] lz=[expo(3,lm[:j]+lm[j+1:],N) for j in range(n)] return
sum([hamming(z) for z in lz])
The function htot gives the following result for small values of k: >>>
[htot(i) for i in range(3,8)][35, 122L, 540L, 2068L, 8070L]
You are scincerely asked to compute the value of function htot for larger
values of k. Go as far as you can.
I am expecting your fast respond.
With Best Regards.
Kalkidan Aweke
+251911505062
Addis Ababa
Ethiopia
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