On Tue, Feb 26, 2013 at 2:08 PM, Donald Stufft <donald.stu...@gmail.com> wrote:
> In [45]: l = [x for x in releases if any([y for y in x[1].split(".") if
> y.startswith("0") and y.isdigit() and not y.endswith("0")])]
>
> In [46]: len(l)
> Out[46]: 1162
>
> Note this doesn't check if they have confusing versions, (e.g. 1.1 and 1.01)
> just if they
> have a segment with a leading 0.

Thanks.  Probably not worth doing again, but should the last part be y
!= "0" to include cases like "010" and "00"?

--Chris
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