urls.py
```
router = routers.DefaultRouter()
router.register('instagram', InstagramViewSet, base_name='instagram')
api_urls =[
url(r'^api-token-auth/', obtain_jwt_token, name='email-to-jwt'),
url(r'^whatever/$', whatever, name='whatever'),
url(r'^', include(router.urls)),
]
urlpatterns = [
url(r'^api/v1/', include(api_urls)),
url(r'^api/v1/docs/', include_docs_urls(title='Diligence API',
patterns=api_urls))
]
```
When I browse to `127.0.0.1:8000/api/v1/docs` and click the Interact button
for my instagram url, I get back a 404 and the Django debug HTML page which
says that the page was not found because the request URL was
`http://127.0.0.1:8000/instagram/text/`. Note that that url is missing the
`api/v1`.
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