I have written the following code in the Django shell:
from rest_framework import serializers
class MySerializer(serializers.Serializer):
choice = serializers.ChoiceField(choices=[(1, 'One'), (2, 'Two'), (3,
'Three')], required=True)
serializer = MySerializer(data={'choice': 'One'})
serializer.is_valid()
serializer.validated_data
Before I executed the code, I expected serializer.is_valid() to return True
and for serializer.validated_data to contain:
OrderedDict([('choice': 1)])
However, it seems that I misunderstood the deserialization behavior of
rest_framework.serializers.ChoiceField because I was surprised to discover
that serializer.is_valid() returns False and that serializer.validated_data
contains:
{}
When I call serializer.is_valid(raise_exception=True), the traceback sheds
some more light on the situation.
Traceback (most recent call last):
File "<console>", line 1, in <module>
File "/path/to/rest_framework/serializers.py", line 243, in is_valid
raise ValidationError(self.errors)
rest_framework.exceptions.ValidationError: {'choice':
[ErrorDetail(string='"One"
is not a valid choice.', code='invalid_choice')]}
Furthermore, when I instantiate serializer as follows:
serializer = MySerializer(data={'choice': 1})
serializer.is_valid() *does* return True and serializer.validated_data
contains
OrderedDict([('choice': 1)])
So I have two questions:
1) Is this the intended deserialization behavior of
rest_framework.serializers.ChoiceField?
2) If so, why does each choice have a separate key and display_name
described here
<https://www.django-rest-framework.org/api-guide/fields/#choicefield> or
how can one resolve a display_name to a key without doing it manually? It's
not that I have a *problem* with doing it manually, but if I *were *to do
it manually, I would feel like I was doing something wrong because I
glanced at the source code and it looks like there is a way to do it
automatically.
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