#22450: Error when model.save(force_insert=True)
----------------------------------------------+----------------------------
     Reporter:  vcajes@…                      |      Owner:  nobody
         Type:  Uncategorized                 |     Status:  new
    Component:  Database layer (models, ORM)  |    Version:  1.6
     Severity:  Normal                        |   Keywords:  model save
 Triage Stage:  Unreviewed                    |  force_insert
Easy pickings:  0                             |  Has patch:  0
                                              |      UI/UX:  0
----------------------------------------------+----------------------------
 I'm having an error when I add the force_insert=True parameter to a
 model.save call. The problem is arising in a Django Unit TestCase (from
 django.test import TestCase)

 The model example:

 {{{
 class Company(models.Model):
         owner = models.ForeignKey(User)
         name = models.CharField(max_length=75)
         description = models.CharField(max_length=250)
         created = models.DateTimeField()
         status = models.CharField(max_length=1,
 choices=COMPANY_STATUS_CHOICES, default='a')

         def save(self, *args, **kwargs):
                 if not self.pk:
                         self.created = timezone.now()
                 super(Company, self).save(args, kwargs)
 }}}

 The code error example:

 {{{
 self.company = Company(owner=self.operator, name="Company1",
 description="Descripcion Company1", status='a')
 self.company.save(force_insert=True)
 }}}

 And the error say it cannot force an '''UPDATE''' (I think there are some
 parameters that are passed in a wrong order somewhere)


 {{{
 Error
 Traceback (most recent call last):
   File "C:\Users\KGs\Documents\Coupoints\wsgi\openshift\points\tests.py",
 line 36, in setUp
     self.company.save(force_insert=True)
   File
 "C:\Users\KGs\Documents\Coupoints\wsgi\openshift\business\models.py", line
 49, in save
     super(Company, self).save(args, kwargs)
   File "C:\VirtualEnvs\CoupointsEnv\lib\site-
 packages\django\db\models\base.py", line 545, in save
     force_update=force_update, update_fields=update_fields)
   File "C:\VirtualEnvs\CoupointsEnv\lib\site-
 packages\django\db\models\base.py", line 573, in save_base
     updated = self._save_table(raw, cls, force_insert, force_update,
 using, update_fields)
   File "C:\VirtualEnvs\CoupointsEnv\lib\site-
 packages\django\db\models\base.py", line 626, in _save_table
     raise ValueError("Cannot force an update in save() with no primary
 key.")
 ValueError: Cannot force an update in save() with no primary key.
 }}}

 The problem is in here:

 In the file django.db.models.base.py in the function:

 {{{
 def _save_table(self, raw=False, cls=None, force_insert=False,
 force_update=False, using=None, update_fields=None):
 }}}

 If you print the parameters force_insert, force_update, update_fields just
 before the:

 {{{
  if not pk_set and (force_update or update_fields):
             raise ValueError("Cannot force an update in save() with no
 primary key.")
 }}}

 You will see that force_insert is None and force_update has the value
 {'force_insert': True}, and thats the problem.

 Its an easy to solve problem. Y just wanted to report. Thanks.

-- 
Ticket URL: <https://code.djangoproject.com/ticket/22450>
Django <https://code.djangoproject.com/>
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