#25383: Trying to access the local server in HTTPS throw a 400 error
--------------------------------------+--------------------
Reporter: mlorant | Owner: nobody
Type: Cleanup/optimization | Status: new
Component: HTTP handling | Version: 1.8
Severity: Normal | Keywords:
Triage Stage: Unreviewed | Has patch: 0
Easy pickings: 0 | UI/UX: 0
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Using the `manage.py runserver` command, when I try to access to
https://127.0.0.1:8000 (note the https protocol), the server throws an
error:
{{{
[11/Sep/2015 16:48:05] code 400, message Bad request syntax
('\x16\x03\x01\x00\xba\x01\x00\x00\xb6\x03\x03k[\xae\x88;\x81\xefJ\xa5\xa5\xa9j[F,uK\xcfb\xf4\x90\xbf\xd9k\x14\x86(w\x00_V0\x00\x00\x1e\xc0+\xc0/\xc0')
----------------------------------------
Exception happened during processing of request from ('127.0.0.1', 35451)
Traceback (most recent call last):
File "/usr/lib/python2.7/SocketServer.py", line 593, in
process_request_thread
self.finish_request(request, client_address)
File "/usr/lib/python2.7/SocketServer.py", line 334, in finish_request
self.RequestHandlerClass(request, client_address, self)
File "my_virtual_env/local/lib/python2.7/site-
packages/django/core/servers/basehttp.py", line 129, in __init__
super(WSGIRequestHandler, self).__init__(*args, **kwargs)
File "/usr/lib/python2.7/SocketServer.py", line 649, in __init__
self.handle()
File "/usr/lib/python2.7/wsgiref/simple_server.py", line 117, in handle
if not self.parse_request(): # An error code has been sent, just exit
File "/usr/lib/python2.7/BaseHTTPServer.py", line 286, in parse_request
self.send_error(400, "Bad request syntax (%r)" % requestline)
File "/usr/lib/python2.7/BaseHTTPServer.py", line 368, in send_error
self.send_response(code, message)
File "/usr/lib/python2.7/BaseHTTPServer.py", line 385, in send_response
self.log_request(code)
File "/usr/lib/python2.7/BaseHTTPServer.py", line 422, in log_request
self.requestline, str(code), str(size))
File "my_virtual_env/local/lib/python2.7/site-
packages/django/core/servers/basehttp.py", line 136, in log_message
msg = "[%s] %s\n" % (self.log_date_time_string(), format % args)
UnicodeDecodeError: 'ascii' codec can't decode byte 0xba in position 5:
ordinal not in range(128)
----------------------------------------
}}}
I don't know if there are limitations about having a local server
supporting the HTTPS protocol, but Django should at least throw a nicer
exception. This error happened to a colleague who modified in his browser
a production URL (which only works in https) to a local one, and the error
was quite cryptic at first sight.
--
Ticket URL: <https://code.djangoproject.com/ticket/25383>
Django <https://code.djangoproject.com/>
The Web framework for perfectionists with deadlines.
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