#28561: .order_by('foo__id') doesn't create a join ------------------------------------------------+------------------------ Reporter: Marten Kenbeek | Owner: nobody Type: Cleanup/optimization | Status: new Component: Documentation | Version: 1.11 Severity: Normal | Keywords: Triage Stage: Unreviewed | Has patch: 0 Needs documentation: 0 | Needs tests: 0 Patch needs improvement: 0 | Easy pickings: 1 UI/UX: 0 | ------------------------------------------------+------------------------ The documentation on `order_by()` states:
> It is also possible to order a queryset by a related field, without incurring the cost of a JOIN, by referring to the _id of the related field: > {{{ > # No Join > Entry.objects.order_by('blog_id') > > # Join > Entry.objects.order_by('blog__id') > }}} However, in recent versions the latter query is optimised and won't create a join: {{{ >>> print(Bar.objects.order_by('foo__id').query) SELECT "foo_bar"."id", "foo_bar"."foo_id" FROM "foo_bar" ORDER BY "foo_bar"."foo_id" ASC }}} -- Ticket URL: <https://code.djangoproject.com/ticket/28561> Django <https://code.djangoproject.com/> The Web framework for perfectionists with deadlines. -- You received this message because you are subscribed to the Google Groups "Django updates" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-updates+unsubscr...@googlegroups.com. To post to this group, send email to django-updates@googlegroups.com. To view this discussion on the web visit https://groups.google.com/d/msgid/django-updates/047.6cfb141958782c00fd3e6d78b26eb394%40djangoproject.com. For more options, visit https://groups.google.com/d/optout.