#29096: JSONField() as base_field for ArrayField() for creating an object array
-------------------------------------+-------------------------------------
               Reporter:  Jim Biggs  |          Owner:  nobody
                   Type:             |         Status:  new
  Uncategorized                      |
              Component:  Core       |        Version:  2.0
  (Serialization)                    |       Keywords:  serialization,
               Severity:  Normal     |  JSONField, ArrayField
           Triage Stage:             |      Has patch:  0
  Unreviewed                         |
    Needs documentation:  0          |    Needs tests:  0
Patch needs improvement:  0          |  Easy pickings:  0
                  UI/UX:  0          |
-------------------------------------+-------------------------------------
 Current Environment:
   • Latest Django-2
   • Latest Django Rest Framework
   • PostgreSQL-9.5
   • Ubuntu-16.04

 My understanding of the JSONField() is that it is a field container for a
 single JSON object. My use-case requires an array of objects. So, I
 created an ArrayField() that nests a JSONField() as its model base_field
 -- as shown in the code block, below:

 {{{
 questions = ArrayField(JSONField(null=True, blank=True, default=dict),
 max_length=200, blank=True, default=[])
 }}}

 Everything seems to work fine with the exception of the JSON object being
 stringified, as shown below:


 {{{
 "questions": [
                 "{
                       \"question\": \"What is the answer to everything?\",
                       \"answer\": \"42\"
                  }",
                 "{
                       \"question\": \"What year is it?\",
                       \"answer\": \"2018\"
                  }"
            ],
 }}}


 I believe the inserted backslashes (\) are a result of the serialization
 process. My question is whether there is a better way for me to define
 this object array model field?

 Regards... Jim

-- 
Ticket URL: <https://code.djangoproject.com/ticket/29096>
Django <https://code.djangoproject.com/>
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