#33912: In the admin, saving an object in a non-default database with unique 
field
fails when the default database contains an object with the same unique
field value but different PK
--------------------------------------------+------------------------
               Reporter:  François Granade  |          Owner:  nobody
                   Type:  Uncategorized     |         Status:  new
              Component:  Uncategorized     |        Version:  4.0
               Severity:  Normal            |       Keywords:
           Triage Stage:  Unreviewed        |      Has patch:  0
    Needs documentation:  0                 |    Needs tests:  0
Patch needs improvement:  0                 |  Easy pickings:  0
                  UI/UX:  0                 |
--------------------------------------------+------------------------
 Reproducible using the test project in https://github.com/farialima
 /django-multidbbug . See README.md on how to run it.

 The steps are:
 - a model with a unique string field (beside the default int PK)
 - two DBs in the settings (`default` and `other`)
 - two objects in the default DB with PK 1 and 2, and some unique value for
 the unique string field
 - a object in the other DB (thus, with PK 1) with a different unique
 string field value
 - in `admin.py`, point the UI to the other database for the model (using
 https://docs.djangoproject.com/en/4.0/topics/db/multi-db/#exposing-
 multiple-databases-in-django-s-admin-interface)
 - in the admin, try modifying the object in the other DB, giving it the
 same unique string value as the object with PK 2 in the default database

 => saving fails with error "Parcel with this Tracking id already exists.",
 see screenshot.

 The underlying issue is clearly that the admin will try to verify in the
 default DB that the objects doesn't exist. I think that the admin should
 *not* look in the default DB, as I set it up to only use the 'other' DB
 for my model...


 ```
  % poetry run ./manage.py shell
 (...)
 >>> from multidbbugapp.models import Parcel
 >>> print(Parcel.objects.all())
 <QuerySet [<Parcel: id=1, tracking_id=one>, <Parcel: id=2,
 tracking_id=two>]>
 >>> print(Parcel.objects.using('other').all())
 <QuerySet [<Parcel: id=1, tracking_id=two-duplicate>]>
 >>> o = Parcel.objects.using('other').first()
 >>> o
 <Parcel: id=1, tracking_id=two-duplicate>
 >>> o.tracking_id = 'two'
 >>> o.save()
 >>>
 ```

-- 
Ticket URL: <https://code.djangoproject.com/ticket/33912>
Django <https://code.djangoproject.com/>
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