#9743: Problem in admin when displaying foreignkey of a model that reference
himself
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Reporter: daniels | Owner: nobody
Status: new | Milestone:
Component: Database layer (models, ORM) | Version: 1.0
Keywords: | Stage: Unreviewed
Has_patch: 1 | Needs_docs: 0
Needs_tests: 0 | Needs_better_patch: 0
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{{{
class Client(models.Model):
name = models.CharField()
class Module(models.Model):
client = models.ForeignKey(Client)
class SuperModule(Module):
sample = models.ForeignKey(Module)
}}}
If in the django.admin.contrib, we want to display SuperModule with a
list_display = ('name', 'client')
it will not work unless we remove the foreign key to Module.
It was not tested with the simple code above, but in our complete code.
After some investigation, I found a way where an error occured when doing
'as_sql()' on a
query_set. The error was about an extra parameter to avoid.update(). And
some lines below,
the same function call but with a small difference in parenthesis and
works OK.
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Ticket URL: <http://code.djangoproject.com/ticket/9743>
Django <http://code.djangoproject.com/>
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