Author: kmtracey
Date: 2009-12-31 13:52:26 -0600 (Thu, 31 Dec 2009)
New Revision: 12036
Modified:
django/trunk/django/test/simple.py
Log:
Ensure the default keyboard interrupt handler is restored
even if the test runner raises an exception. Thanks Alex
Gaynor.
Modified: django/trunk/django/test/simple.py
===================================================================
--- django/trunk/django/test/simple.py 2009-12-31 19:23:23 UTC (rev 12035)
+++ django/trunk/django/test/simple.py 2009-12-31 19:52:26 UTC (rev 12036)
@@ -27,8 +27,10 @@
"""
self._default_keyboard_interrupt_handler = signal.signal(signal.SIGINT,
self._keyboard_interrupt_handler)
- result = super(DjangoTestRunner, self).run(*args, **kwargs)
- signal.signal(signal.SIGINT, self._default_keyboard_interrupt_handler)
+ try:
+ result = super(DjangoTestRunner, self).run(*args, **kwargs)
+ finally:
+ signal.signal(signal.SIGINT,
self._default_keyboard_interrupt_handler)
return result
def _keyboard_interrupt_handler(self, signal_number, stack_frame):
--
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