Thank you very much :-) Joakim
On Jun 5, 4:42 pm, johan de taeye <johan.de.ta...@gmail.com> wrote: > Typo... > The correct syntax is : > obj_list = [ i for i in MyObject.objects.all() if my_filter(i) ] > > On Jun 5, 4:29 pm, johan de taeye <johan.de.ta...@gmail.com> wrote: > > > Possible through basic Python: > > > obj_list = [ i for i in MyObject.objects.all() where my_filter(i) ] > > > Note that this filtering is happening on the Python side of things, > > whereas a queryset filter is executed in SQL on the database. The > > filtering on the database is normally much, much faster, so be careful > > with the python-style filtering... > > > Johan > > > On Jun 5, 12:32 pm, Joakim Hove <joakim.h...@gmail.com> wrote: > > > > Hello, > > > > I have a query list which I want to filter based on a computation > > > which I supply: > > > > # Create a query set containing everything: > > > obj_list = MyObject.objects.all() > > > > # Now - select only the element which pass some test: > > > obj_list = obj_list.filter( my_filter ) > > > > def my_filter( obj ): > > > # Does a computation based on obj values, and returns true or > > > false > > > .... > > > return true|false > > > > Is something like this doable? > > > > Joakim- Hide quoted text - > > > - Show quoted text - -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-us...@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.