I thought you were trying to get: I'm expecting only the four distinct records.
You'll get a ValuesQuerySet or list of dictionaries with redundant keys this way. Thanks, Subhranath Chunder. On Wed, Jul 21, 2010 at 11:40 PM, rmschne <[email protected]> wrote: > Member.objects.values('status').order_by('status').distinct() from > jaymzcd works perfectly. Thanks! > > -- > You received this message because you are subscribed to the Google Groups > "Django users" group. > To post to this group, send email to [email protected]. > To unsubscribe from this group, send email to > [email protected]<django-users%[email protected]> > . > For more options, visit this group at > http://groups.google.com/group/django-users?hl=en. > > -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
