On 19 October 2010 19:06, Valentin Golev <[email protected]> wrote:
> Hello,
>
> I'm trying to start using new class based views from the trunk.
>
> I need to rewrite a view which is decorated
> django.contrib.auth.decorators.login_required.
>
> How should I go with that?
There are couple of options.
1) decorate the final view (for use in urls.py):
decorated_view = login_required(MyView.as_view)
In this option, you lose the ability to subclass the decorated view.
2) decorate the dispatch method. You need to turn login_required into
a method decorator first (Django should probably provide a tool for
this). Here[1] is an example how to do this.
class MyDecoratedView(MyView):
@on_method(login_required):
def dispatch(self, *args, **kwargs):
# do any extra stuff here
return super(MyDecoratedView, self).dispatch(*args, **kwargs)
3) Make a class decorator, that does the above, so you could do:
@on_dispatch(login_required)
class MyDecoratedView(MyView):
pass
>
> I was going to write something like LoginRequiredMixin, but I have no
> idea how to do this. I need to run my code before .dispatch(), but I
> also have to call the old dispatch, but since Mixin aren't inherited
> from View, I can't just override method and use super().
This is option #4. You can just do:
class LoginRequiredMixin(object):
def dispatch(self, *args, **kwargs):
bound_dispatch = super(LoginRequired, self).dispatch
return login_required(bound_dispatch)(*args, **kwargs)
[1]: http://www.toddreed.name/content/django-view-class/
--
Łukasz Rekucki
--
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to
[email protected].
For more options, visit this group at
http://groups.google.com/group/django-users?hl=en.