Well, Bruno, if I knew exactly how to solve this I wouldn't be sitting here
taking your snooty remarks, would I? I am asking because I do not know how
to go about it.

On Fri, Nov 26, 2010 at 4:50 PM, bruno desthuilliers <
[email protected]> wrote:

>
>
> On 26 nov, 15:03, Sithembewena Lloyd Dube <[email protected]> wrote:
> > I found the issue: it is the path to the image. When I change the problem
> > line to
> >
> > image = Image.open(os.path.realpath('C:\Users\Lloyd\Desktop\Lloyd.png'))
> >
> > it works,
>
> Well, kinda... accidentally...
>
> > but I cannot hard code the path and I cannot predict where the
> > user will try to upload a file from.
>
> That's not exactly the problem, but the mere fact you think you could
> solve your problem that way says a lot about your misunderstanding of
> the HTTP protocol.
>
>
> > Isn't there a way to dynamically get
> > the path from the file upload dialogue where the user browses to it and
> > selects it?
>
> What would you do with this information ? Do you really think the
> server on which your application will be deployed will have any access
> to the client's filesystem ???
>
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-- 
Regards,
Sithembewena Lloyd Dube
http://www.lloyddube.com

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