On Dec 3, 11:13 am, oscar widjaya <[email protected]> wrote:
> It's for mysql
> it still does not work. I tried it with the following sql statement
> "SELECT * FROM project_project WHERE start_date LIKE '%s'" % '2010%%'

Well, I assume that the double % at the end of your query is
unintentional, as I don't think it should be there, but I'm not an sql
guru.

I just know that when I was having to craft some custom sql a couple
of months ago (using Postgres) I had to toy with the formatting a bit
to get it working.  I also had to make sure I passed everything as a
str, and not unicode.

Maybe someone else how knows sql better will come along.

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