{%  for Ltarp in  smth.3 %}
SHOULD BE 
{%  for Ltarp in  smth.2 %}
'cos Lans only has 3 elements and Ltarp is Lans[2].

Chris

-----Original Message-----
From: django-users@googlegroups.com [mailto:django-us...@googlegroups.com] On 
Behalf Of gintare
Sent: 07 January 2011 08:52
To: Django users
Subject: list of lists in template


in view.py
...
Ltarp.append([item.Wordword, item.WordTranslEn, item.WordNotesGram,
item.WordConcl])
..
Lans.append([sen.Sent, sen.SentTransl, Ltarp ] )

in template.html
{% if Lans %}

{%  for smth in Lans %}
<table >
<tr> <td width='500'> {{smth.0}} </td></tr>

    {%  for Ltarp in  smth.3 %}
    <tr>
    <td width='500'> {{Ltarp.0}} </td>

    </tr>
    {% endfor %}

</table>
{% endfor %}

{% endif %}

###########################

the rows from smth.0 are shown
the rows from  Ltarp in  smth.3, i.e. {{Ltarp.0}} are not shown.

I tried also:Ltarp, Ltarp[0], smth.Ltarp.0

nothing works in the second for cycle where i need to get items from
list built in third item of list in the first for cycle.

Could you please help with syntax, when i need to dislay item from
list in another list in template

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