For other to use, the final version for downloading the file is
bellow. ReferenceFile is my model.
import mimetypes
from django.core.servers.basehttp import FileWrapper
from django.http import HttpResponse
def download(request, id):
file_to_download = get_object_or_404(ReferenceFile, pk=id)
if file_to_download.filename_orig is not None:
filename = '%s/%s' % (MEDIA_ROOT,file_to_download.file.path)
wrapper = FileWrapper(open(filename))
content_type = mimetypes.guess_type(filename)[0]
response = HttpResponse(wrapper,content_type=content_type)
response['Content-Length'] = os.path.getsize(filename)
response['Content-Disposition'] = "attachment; filename=%s" %
file_to_download.filename_orig
return response
[...]
On 11 feb., 16:15, Tom Evans <tevans...@googlemail.com> wrote:
> On Fri, Feb 11, 2011 at 2:05 PM, Gabriel - Iulian Dumbrava
>
> <gabriel.dumbr...@gmail.com> wrote:
> > I found a solution on the second part, sending the file back to the
> > user with the original filename here:
> >http://stackoverflow.com/questions/1156246/having-django-serve-downlo...
>
> > I would still need some help on the first part.
>
> > Thanks,
> > Gabriel
>
> http://docs.djangoproject.com/en/1.2/ref/models/fields/#django.db.mod...
>
> """
> This may also be a callable, such as a function, which will be called
> to obtain the upload path, including the filename. This callable must
> be able to accept two arguments, and return a Unix-style path (with
> forward slashes) to be passed along to the storage system. The two
> arguments that will be passed are…
> """
>
> Cheers
>
> Tom
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