Example code:

   class Parent(models.Model):
        name = models.CharField(max_length='20',blank=True)

    class Child(Parent):
        pass

I want to get the result of Child.objects.all() but I DO NOT want to
use Child.
I want to use Parent instead, which I tried to do with:

    Parent.objects.filter(child__isnull=False)

Which doesn't work and gives the result of Product.objects.all()
instead.
However If I do the following, it WORKS:

    Parent.objects.filter(child__name__isnull=False)

Another way, if I insist on using
Parent.objects.filter(child__isnull=False), is to change the Child
model to the following:

    class Child(models.Model):
        parent = models.OneToOneField(Parent)

Then Parent.objects.filter(child__isnull=False) would WORK

The problem with the 2 solutions above is that filtering with
child__name__isnull looks hackish, and I don't want to change my Child
model to use OneToOneField.

So is there a better way?

Thanks,
Robin

-- 
You received this message because you are subscribed to the Google Groups 
"Django users" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to 
[email protected].
For more options, visit this group at 
http://groups.google.com/group/django-users?hl=en.

Reply via email to