This is my template:
{% block content %}
<h2>Report Writing Types</h2>
<ul>
{% for type in object_list %}
<li>{{ type.name }} <a href="/reportwriting/types/edit/
{{ type.id }}/?next={{request.path}}?page={{ page_obj.number }}">Edit</
a></li>
{% endfor %}
</ul>
<div class="pagination">
<span class="step-links">
{% if page_obj.has_previous %}
<a href="?
page={{ page_obj.previous_page_number }}">previous</a>
{% endif %}
<span class="current">
Page {{ page_obj.number }} of
{{ page_obj.paginator.num_pages }}.
</span>
{% if page_obj.has_next %}
<a href="?page={{ page_obj.next_page_number }}">next</a>
{% endif %}
</span>
</div>
{% endblock %}
And this is my urls.py:
url(r'^reportwriting/types/$', ListView.as_view(
model=Type, paginate_by=2
)),
url(r'^reportwriting/types/edit/(?P<pk>\d+)/?$',
UpdateView.as_view(
model=Type
)),
The URL I am trying to return to the following URL after successful
form submission:
/reportwriting/types/?page=2
is this possible please?
Thanks for any assistance.
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