Dear users,
I have simple question which regards with running script from view.py.
Part of my view.py looks like:
def updateSystem(request):
print request.POST
id = 20
idgrp = 0
print "ID: %d and IDGRP: %d" % (id, idgrp)
if request.is_ajax():
message = "This is AJAX part"
if request.method == 'POST':
query = request.POST
print query.items()
try:
sysid=51
output = subprocess.Popen(['/home/user/djcode/testlab/
updateSys','-sysid','%d','-id','%d','-idgrp','%d' % (sysid,id,idgrp)],
shell = False, stdou=subprocess.PIPE)
test,err = output.communicate()
print output.returncode
print err
print test
except OSError:
return HttpResponse("Wrong command")
print "CORRECT REQUEST: %s" % query.get('data','sysid=0')
message = "Content-type text/html\n\n"
return HttpResponse(message)
else:
return HttpResponse(status=400)
else:
message = "This is not AJXA"
return HttpResponse(status=400)
Is it possible to do that over subprocess command?
>From the command line script updateSys written in Python as well
should return list of directory.
Thank you
best regards
Petr
--
You received this message because you are subscribed to the Google Groups
"Django users" group.
To post to this group, send email to [email protected].
To unsubscribe from this group, send email to
[email protected].
For more options, visit this group at
http://groups.google.com/group/django-users?hl=en.