Hi, I am trying to implement a menu system for my project which would enable the admin to create menu's that will be displayed on the webpage. So i should be able to create sub-menus which will have a parent menu. My table structure will be as follows
id name url parent_id Here the parent_id will be the id of the menu of the same table. So on the admin area i want a select box for the parent_id which will display the already entered records. How can it be done? Thanks and Regards, Swaroop Shankar V -- You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com. To unsubscribe from this group, send email to django-users+unsubscr...@googlegroups.com. For more options, visit this group at http://groups.google.com/group/django-users?hl=en.
