Gnissem wrote: > I am using generic views to produce a paginated specimen list. In the > list, you can click on a specimen to get the generic view detail. > After viewing the detail, the user will likely want to go back to the > specimen list, on the page where the link came from. Pressing the back > button works, but I'd like to give the user a link to take them back. > How do I go this? > > I tried passing the page number from the generic list view into the > generic detail view with a url like: /specimen/244/?page=7. However > there does not seem to be any way to access GET data in the template. > Since there is no view, it can't be retrieved there and passed to the > template. (And in general it seems like it would be nice to pass GET > values directly into a template without needing the intervention of a > view. Is this possible? > > Thanks in advance for help. I am new to Django so excuse me if I have > missed something obvious....
You need to wrap the generic detail view with your own detail view which passes the specific GET variable you need through the "extra_context" dictionary. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "Django users" group. To post to this group, send email to django-users@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/django-users -~----------~----~----~----~------~----~------~--~---
