Hello~
I need to run the python django project and meanwhile accept the
socket connection from somewhere to receive data.
But I dont know is this can be done,so any tips if this is possible?
thanks~
kay
On 12月27日, 下午4時34分, Vovk Donets <donets.vladi...@gmail.com> wrote:
> For what you need this?
> Maybe you should consider using Celery for doing background jobs.
>
> 2011/12/23 Kay <fcapba1...@gmail.com>
>
>
>
>
>
>
>
>
>
> > if I have easy asyncore socket code as follow:
>
> > ---------------------------------------------------------------------------
> > -----------------------------------
>
> > import socket
> > import asyncore
>
> > class asysocket(asyncore.dispatcher):
>
> > def __init__(self,host,port):
> > asyncore.dispatcher.__init__(self)
> > self.create_socket(socket.AF_INET, socket.SOCK_STREAM)
> > self.set_reuse_addr()
> > self.bind((host, port))
> > self.listen(10)
> > print 'server is waiting for socket connection...'
>
> > def handle_accept(self):
> > new,addr = self.accept()
> > print 'received from address', addr
> > data = new.recv(1024)
> > print repr(data)
>
> > def handle_close(self):
> > self.close()
>
> > server = asysocket('127.0.0.1',1234)
> > asyncore.loop()
>
> > ---------------------------------------------------------------------------
> > -------------------------------------
>
> > then how to use this in my django project views.py to let it
> > automatically work for receiving connection
>
> > while i start the project as "python manage.py runserver [port]"??
>
> > thanks
>
> --
> *Vovk Donets*
> python developer
>
> skype: suunbeeam
> icq: 232490857
> mail: donets.vladi...@gmail.com
> www: jetfix.ru
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