Perhaps a filter rather than a tag. You will need to provide input
for the filter, but it can ignore it. So:
{% for a in random_variable|list_print %}
Bill
On 2/19/12, brian <brian.down...@yakkadesign.com> wrote:
> Is it possible to create a template tag that will create a list that a
> for loop can loop over? I know I can create a template tag that will
> store the list in a variable and then iterate over that variable. I
> want to do it in one step.
>
> For example the template tag with be “list_print” that will create a
> list. I want something like the following in the template:
> {% for a in list_print %}
>
> Below is my code. When I call it the loop never iterates.
> @register.tag(name="list_print")
> def do_list_print(parser, token):
> #test that don't have arguments
> try:
> tokenList = token.split_contents()
>
> except Exception:
> raise template.TemplateSyntaxError("%r tag throw unexpected
> exception(token.split_contents)" % token.contents.split()[0])
>
> if len(tokenList)>1:
> raise template.TemplateSyntaxError("%r tag does not take
> arguments" % token.contents.split()[0])
>
> return ListPrintNode()
>
> class ListPrintNode(Node):
> """
> thread safe version based on CycleNode from
> https://docs.djangoproject.com/en/dev/howto/custom-template-tags/
> """
>
> def __init__(self):
> self.myList = ['a', 'b']
>
> def render(self, context):
>
> if self not in context.render_context:
> context.render_context[self] =
> itertools.cycle(self.myList)
>
> cycle_iter = context.render_context[self]
> return cycle_iter.next()
>
> Brian
>
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