4.5.2012 1:22, psychok7 kirjoitti:
hi i have done a succefull query and i converted the results into links
so i can make a post by clicking on the links to make a reservation.
No, you haven't. When you click you'll still send very much standard GET
request to server. You can and should verify that by using some
debugging console.
my problem is, theres a variable timeout that i want to specify
manually, but i get a "Key 'timeout' not found in <QueryDict: {}>"
i know i am supposed to pass that variable but i just dont know how.
my code is :
def reserve (request,user_id,park_id):
#only works if the user exists in database
u = get_object_or_404(User, pk=user_id)
n = get_object_or_404(Notification, pk=park_id)
p = get_object_or_404(Park, pk=1)
r = Reservation(user=u ,notification=n, park=p,
timeout=int(request.POST['timeout']),active=True,parked=False,reservation_date=datetime.now())
r.save()
return HttpResponse('Spot reserved')
html:
{% if parks %} <p>You searched for: <strong>{{ query }}</strong></p>
<p>Found {{ parks|length }} park{{ parks|pluralize }}.</p> <ul> {% for
park in parks %} <input type="text" name="timeout" value="60"
id="timeout"> <li><a href="/accounts/{{ user.id }}/reserve/{{ park.id
}}">{{ park.park_address }}</a></li> {% endfor %} </ul> {% endif %}
can someone help me?
If above is your true HTML and nothing removed you're just creating list
of standard links.
If you want to pass additional parameters there is few ways to achieve it:
a) You can modify your sent url by javascript and add timeout manually
to get query parameters.
b) You transform your links to selectable list/dropdown and create real
HTML form to send post with real submit button.
c) Hybrid of a and b. I won't go into details since it would be just a mess.
--
Jani Tiainen
- Well planned is half done and a half done has been sufficient before...
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