The obvious ways are:
1. Provide a model method that returns a string representing the type
of the instance, compare against that
2. Decorate the instance with an attribute giving the name of the type
as a string...
Can't change the instance (I really think you can still decorate it in
the view, python is flexible that way, but), instead of rows of
instances, return rows of wrapper objects that have the type name as
above, and the original instance as another attribute.
On Tue, Jul 3, 2012 at 3:50 PM, Russ Abbott <russ.abb...@gmail.com> wrote:
> I'm generating a table. I want the cells to be different depending on the
> type of the content. How do I test for the type of the content? I'd like to
> do something like this.
>
> <tbody>
> {% for row in rows %}
> <tr>
> {% for cell in row %}
> <td>
> {% if isinstance( {{ cell }}, list) %}
> <ul>
> {% for element in cell %}
> <li>{{ element }}</li>
> {% endfor %}
> <ul>
> {% else %}
> {{ cell }}
> {% endif %}
> </td>
> {% endfor %}
> </tr>
> {% endfor %}
> </tbody>
>
> But "{% if isinstance( {{ cell }}, list) %}" is not allowed. Apparently I
> can't call a function in an {% if ... %} tag. Is there another way to do
> this?
>
> Thanks.
>
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