I just know this is a dumb question, but...

What I want is something like
file = models.FileField(upload_to="img/memorabilia/+self.slug")

But I just no that can't be right? Can this be done? How?


--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups 
"Django users" group.
To post to this group, send email to [email protected]
To unsubscribe from this group, send email to [EMAIL PROTECTED]
For more options, visit this group at 
http://groups.google.com/group/django-users
-~----------~----~----~----~------~----~------~--~---

Reply via email to