Thanks Malcom. Actually somebody in the IRC showed me how to do  
exactly what I want with this:

if the_thing != the_other_thing:
        raise StandardError ('This function doesn't work. Please fix it.')

Does exactly what I wanted :-)

Thanks guys!

Sean


On Sep 16, 2006, at 8:15 PM, Malcolm Tredinnick wrote:

>
> On Sat, 2006-09-16 at 19:10 +0900, Sean Schertell wrote:
>> Maybe I'm going about this the wrong way. All I want to do is exit
>> the script and barf a big ugly error to the screen or the log in the
>> event that something uncool happens.
>>
>> So for example, let's say in my view I have a function to calculate
>> area:
>>
>> def calculate_area(width, height):
>>      if not width and height:
>>              raise ('Unable to calculate area -- missing parameters')
>>      else:
>>              return width * height
>>
>> But then I just get a nasty 500 error (using apache/mod_python in dev
>> mode) and my error string doesn't get displayed or logged anywhere
>> either.
>
> The return from a view must be an HttpResponse or derivative instance.
> If you want something to go to the your server error logs, then  
> normally
> you would send it to sys.stderr. In that case, you still need to  
> return
> an HttpResponse from your view, since that controls what is sent  
> back to
> the client.
>
> Django has one shortcut here, which is that you can raise a
> django.http.Http404 exception for a missing page. But for all other
> status codes, either create your own HttpResponse instance (setting  
> the
> status_code attribute to whatever you want), or use one of the
> pre-defined ones from django/http/__init__.py, such as
> HttpResponseServerError, and return that (note *return*, not *raise*).
>
> Regards,
> Malcolm
>
>
>
> >
>
>

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