hi, the basic is the same with full html site, except in ajax you only render part of your html output.
so in ajax you can use ajax call the target url, and the output from the html output is display in the div specified. use jquery or prototype for easy manipulation. hope help Sent from my iPhone On 11 Feb 2013, at 07:04, Amit <pathakami...@gmail.com> wrote: > Hi, > > Javascript does not understand django template syntax. In your case you can > return a template rendered with django, and replace the html. > > Thannks, > > On Sunday, February 10, 2013 3:12:47 PM UTC+5:30, doniyor wrote: > hey guys, i am stuck in this problem. i posted the problem on > stackoverflow.com also, > http://stackoverflow.com/questions/14787772/sorting-queryset-of-search-result-and-render-back-thru-ajax > > but till now no one could answer there, so i am asking here again. anyone can > help me? :( > -- > You received this message because you are subscribed to the Google Groups > "Django users" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to django-users+unsubscr...@googlegroups.com. > To post to this group, send email to django-users@googlegroups.com. > Visit this group at http://groups.google.com/group/django-users?hl=en. > For more options, visit https://groups.google.com/groups/opt_out. > > -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to django-users+unsubscr...@googlegroups.com. To post to this group, send email to django-users@googlegroups.com. Visit this group at http://groups.google.com/group/django-users?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
