FYI: OS=Mac OSX 107, Python 2.7.1 Experience : CGI programming 17 years, python 10 years. Django, FastCGI - newbie .htaccess - pretty shaky
I'd like to work with django out of the box as fastcgi. I have a test site set up. With (code) python manage.py runserver 8000 (/code) My test sites is accessible by http://localhost:8000 With .htaccess as follows (code) AcceptPathInfo On Options +SymLinksIfOwnerMatch DirectoryIndex test0_Loader.py AddHandler fcgid-script .py RewriteEngine on RewriteCond $1 !^(test0_Loader\.py|images|css|js|robots\.txt|favicon\.ico) RewriteCond %{REQUEST_FILENAME} !-f RewriteCond %{REQUEST_FILENAME} !-d RewriteRule ^(.*)$ ./test0_Loader.py/$1 [L,QSA] (/code) If I point my browser to http://localhost/test0 I get the source code for test0_Loader.py printed to the screen. NOTE: Although the (code) python manage.py runserver (/code) method works fine for development, but for deployment, I will be on shared hosting without any port numbers open but the default. mod_fastcgi is enabled for apache. I could use some direction here. thanks -- Tim tim at tee jay forty nine dot com or akwebsoft dot com http://www.akwebsoft.com -- You received this message because you are subscribed to the Google Groups "Django users" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/django-users?hl=en. For more options, visit https://groups.google.com/groups/opt_out.
