That is weird. I don't know why 2 shouldn't satisfy a need for 2.
As far as a work around goes, one doesn't need to use url() to make a url
pattern.
Just a tuple with those two members will do it. I think of url() as a way
to
specify a pattern name without specifying the extra dict.
Unless things have changed.
But I think that your call to patterns() is wrong. The patterns are
additional
arguments, not a list of patterns, at least as normally used. So:
urlpatterns = patterns("", *url_list)
On Fri, Mar 8, 2013 at 2:03 PM, Serge G. Spaolonzi <[email protected]>wrote:
> I am looking the way to create urls on the fly.
> This is a simplified version of the code I am using:
>
> def get_urls():
> url_list = []
> for code in external_code_list:
> url_list.append(
> url(r'^%s/$' % code,
> view
> )
> )
> urlpatterns = patterns('', url_list)
> return urlpatterns
>
>
> urlpatterns = get_urls()
>
> It throws "url() takes at least 2 arguments (2 given)"
>
> Any idea?
>
> Thanks
>
> --
> Serge G. Spaolonzi
> Cobalys Systems
> http://www.cobalys.com
>
> --
> You received this message because you are subscribed to the Google Groups
> "Django users" group.
> To unsubscribe from this group and stop receiving emails from it, send an
> email to [email protected].
> To post to this group, send email to [email protected].
> Visit this group at http://groups.google.com/group/django-users?hl=en.
> For more options, visit https://groups.google.com/groups/opt_out.
>
>
>
--
You received this message because you are subscribed to the Google Groups
"Django users" group.
To unsubscribe from this group and stop receiving emails from it, send an email
to [email protected].
To post to this group, send email to [email protected].
Visit this group at http://groups.google.com/group/django-users?hl=en.
For more options, visit https://groups.google.com/groups/opt_out.
