Re: django template loop collections.defaultdict(lambda: collections.defaultdict(list))

[Daviddd]

I solved in this way:

    my_dict = collections.defaultdict(lambda: collections.defaultdict(list))

    for obj in queryset:
        
my_dict[int(obj.position.split('-')[0])][int(obj.position.split('-')[2])].append(obj)

    for obj in my_dict:            
        my_dict[obj].default_factory = None

    return Response({'queryset': dict(my_dict)}, 
template_name='_internal_template.html')


{% for groups in queryset.itervalues  %}

    groups = {{ groups }}    
    <br><br>

    {% for cols in groups.itervalues  %}

      cols = {{ cols }}    
      <br><br>

      {% for obj in cols  %}

        obj = {{ obj}} in <br><br>
        obj info = {{ obj.title }}, {{ obj.abstract }}<br>

      {% endfor %}      

    {% endfor %}
{% endfor %}


Linked question using default_factory: 
http://stackoverflow.com/questions/4764110/django-template-cant-loop-defaultdict

Thanks!

On Monday, August 26, 2013 12:46:30 PM UTC+2, tom wrote:
>
> On Monday, 26 August 2013, Daviddd wrote:
>
>> Sincerely, I don't know how I can create the dict without using 
>> defaultdict.
>>
>> D
>>
>
> You can create it using a defaultdict if you want to, but once it is 
> created, and before you pass it to the template, loop through all the 
> values of your outer dict and coerce them to dicts using dict(). You are 
> already doing this for your outer defaultdict, which is why the first loop 
> works in your template.
>

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